Practice a real question • free

Learn faster with bite‑sized practice that actually sticks.

StudyBits turns courses into short lessons + interactive questions. Try one below, then keep going with the full course.

Build your own course
Interactive
Answer, get feedback, and move on.
Personalized
Create courses tailored to your goals.
Track progress
Stay consistent with streaks + goals.
Try a sample question
Answer it, then continue the course

Compound-Unit Conversions (Like Speed!) Using Dimensional Analysis

Ever looked at a speed like 15 m/s and thought, “Cool… but what is that in km/h?”

Good news: compound-unit conversions (units with a fraction, like “per second”) are super friendly once you learn one trick:

Dimensional analysis = multiply by “1” in a clever way so the units cancel.


The Big Idea: Multiply by Conversion Factors That Equal 1

A conversion factor is a fraction like:

1000 m1 km\frac{1000\ \text{m}}{1\ \text{km}}

This equals 1 (because 1000 m is 1 km), so multiplying by it changes units without changing the actual value.

The magic is in unit cancellation, like:

m×kmm=km\text{m} \times \frac{\text{km}}{\text{m}} = \text{km}


A Simple Template for Compound Units

For something like:

distancetime\frac{\text{distance}}{\text{time}}

You can convert:

  • the numerator (top)
  • the denominator (bottom)

Template (two-part thinking)

If you have:

A mB s\frac{A\ \text{m}}{B\ \text{s}}

Convert meters to kilometers, and seconds to hours:

A mB s×(1 km1000 m)×(3600 s1 h)\frac{A\ \text{m}}{B\ \text{s}} \times \left(\frac{1\ \text{km}}{1000\ \text{m}}\right) \times \left(\frac{3600\ \text{s}}{1\ \text{h}}\right)

Notice the second factor looks “flipped” compared to what you might expect. That’s because we’re converting seconds in the denominator into hours in the denominator—so we multiply by a factor that cancels s and leaves h down there.


Example 1: Convert m/s\text{m/s} to km/h\text{km/h} (Step-by-step)

Convert:

12 m/skm/h12\ \text{m/s} \to \text{km/h}

Start with the number and units:

12 ms12\ \frac{\text{m}}{\text{s}}

Now multiply by conversion factors that cancel m and s:

12 ms×1 km1000 m×3600 s1 h12\ \frac{\text{m}}{\text{s}} \times \frac{1\ \text{km}}{1000\ \text{m}} \times \frac{3600\ \text{s}}{1\ \text{h}}

Watch the units cancel (this is the whole point)

12 ms×1 km1000 m×3600 s1 h=12 kmh×3600100012\ \frac{\cancel{\text{m}}}{\cancel{\text{s}}} \times \frac{1\ \text{km}}{1000\ \cancel{\text{m}}} \times \frac{3600\ \cancel{\text{s}}}{1\ \text{h}} = 12\ \frac{\text{km}}{\text{h}} \times \frac{3600}{1000}

Now do the math:

12×36001000=12×3.6=43.212 \times \frac{3600}{1000} = 12 \times 3.6 = 43.2

Final:

12 m/s=43.2 km/h12\ \text{m/s} = 43.2\ \text{km/h}


Example 2: Convert km/h\text{km/h} to m/s\text{m/s}

Convert:

90 km/hm/s90\ \text{km/h} \to \text{m/s}

Write it as a fraction:

90 kmh90\ \frac{\text{km}}{\text{h}}

Multiply by factors that cancel km and h:

90 kmh×1000 m1 km×1 h3600 s90\ \frac{\text{km}}{\text{h}} \times \frac{1000\ \text{m}}{1\ \text{km}} \times \frac{1\ \text{h}}{3600\ \text{s}}

Unit cancellation:

90 kmh×1000 m1 km×1 h3600 s=90 1000 m3600 s90\ \frac{\cancel{\text{km}}}{\cancel{\text{h}}} \times \frac{1000\ \text{m}}{1\ \cancel{\text{km}}} \times \frac{1\ \cancel{\text{h}}}{3600\ \text{s}} = 90\ \frac{1000\ \text{m}}{3600\ \text{s}}

Compute:

90×10003600=90×13.6=2590 \times \frac{1000}{3600} = 90 \times \frac{1}{3.6} = 25

Final:

90 km/h=25 m/s90\ \text{km/h} = 25\ \text{m/s}


Chemistry-Style Example: Convert mg/mL\text{mg/mL} to g/L\text{g/L}

This kind of conversion shows up all the time in labs and medication labels.

Convert:

7.5 mg/mLg/L7.5\ \text{mg/mL} \to \text{g/L}

Start:

7.5 mgmL7.5\ \frac{\text{mg}}{\text{mL}}

We want g on top and L on bottom.

Use:

  • 1000 mg=1 g1000\ \text{mg} = 1\ \text{g}
  • 1000 mL=1 L1000\ \text{mL} = 1\ \text{L}

Chain them with cancellation:

7.5 mgmL×1 g1000 mg×1000 mL1 L7.5\ \frac{\text{mg}}{\text{mL}} \times \frac{1\ \text{g}}{1000\ \text{mg}} \times \frac{1000\ \text{mL}}{1\ \text{L}}

Now cancel units:

7.5 mgmL×1 g1000 mg×1000 mL1 L=7.5 gL7.5\ \frac{\cancel{\text{mg}}}{\cancel{\text{mL}}} \times \frac{1\ \text{g}}{1000\ \cancel{\text{mg}}} \times \frac{1000\ \cancel{\text{mL}}}{1\ \text{L}} = 7.5\ \frac{\text{g}}{\text{L}}

Nice surprise: the 1000s cancel, so the number stays the same.

Final:

7.5 mg/mL=7.5 g/L7.5\ \text{mg/mL} = 7.5\ \text{g/L}


How to Choose Conversions That Keep Numbers Clean

A couple friendly tips to reduce rounding and headaches:

1) Use exact metric relationships when you can

These are exact (no rounding needed):

  • 1 km=1000 m1\ \text{km} = 1000\ \text{m}
  • 1 L=1000 mL1\ \text{L} = 1000\ \text{mL}
  • 1 g=1000 mg1\ \text{g} = 1000\ \text{mg}

2) Chain factors so units cancel smoothly

If units cancel like dominoes, you’re doing it right.

3) Prefer one “clean” chain over many repeated steps

Doing everything in one line often reduces intermediate rounding.


Quick Reasonableness Checks (Your Built-in Sanity Filter)

These quick checks help you catch flipped factors instantly:

Speed gut-check

A key anchor:

1 m/s3.6 km/h1\ \text{m/s} \approx 3.6\ \text{km/h}

So:

  • converting m/s → km/h should make the number bigger (multiply by 3.6)
  • converting km/h → m/s should make the number smaller (divide by 3.6)

Concentration gut-check (mg/mL ↔ g/L)

Because both numerator and denominator scale by 1000 in opposite ways, mg/mL and g/L are numerically equal:

1 mg/mL=1 g/L1\ \text{mg/mL} = 1\ \text{g/L}

So if your number changes there, something likely got flipped.


Takeaway

Compound-unit conversions look fancy, but they’re really just:

  1. write the unit as a fraction
  2. multiply by conversion factors that equal 1
  3. cancel units until the target unit is left
  4. do a quick “does this direction make sense?” check

Once you start watching the units cancel, it feels less like math and more like solving a little puzzle—one that always plays fair.

Course
General Chemistry Foundations: Quantitative Concepts & Problem S
10 units51 lessons
Topics
Chemistry (General Chemistry)Physical Chemistry (foundations: thermochemistry/thermodynamics, equilibrium concepts)Chemical Education / Quantitative Reasoning (measurement, units, sig figs, problem-solving methods)
About this course

This course builds a quantitative foundation for general chemistry through measurement, units, dimensional analysis, and significant figures, emphasizing reliable multi-step calculation setup. Core atomic theory is developed from subatomic structure through electron configurations and periodic trends explained by effective nuclear charge. Chemical bonding and molecular structure are treated via Lewis structures, formal charge (intro), resonance (intro), VSEPR, polarity, and intermolecular forces linked to macroscopic properties. Reaction chemistry centers on balancing equations, stoichiometry, limiting reactants, and yields, then extends to gases, phase behavior, solutions and molarity-based calculations, introductory equilibrium and acid–base concepts, and thermochemistry/intro thermodynamics using calorimetry and enthalpy.